| Oh boy!
The engine won't help now. I hope someone in this outfit had enough physics
to calculate the speed necessary to reach the other ramp.
Lucky you... you just got recruited for the team! Here's the data: the take-off ramp is at an angle of 30° and the distance between the ramps is 30 meters. There will be a 30% bonus in your paycheck if you get it right! By the way, the take-off and landing ramps are at the same level. |
This one's
tricky! Time-of-flight will be t = 2(vy / g) and dx
= 30 m = (vx ) t .
Substitute for t in the second equation to get d = (2vy vx ) / g Also, vy = vx tan 30°, so substitute for vy in the above equation and solve for vx . Once you have the components of velocity, use the Pythagorean theorem to obtain (drum roll...) 18.5 m/s (at 30°). By the way, this is about 42 mi/hr. |