| ...and your
nose to the grindstone. Will these trajectory problems never end? Well,
the answer is obvious for today!
This one is simple, though. If the golf ball when hit obtains a velocity of 40 m/s at an angle of 30 degrees, tell me two things: how high does it get and how far does it go? Now, come on! You know how to do this... time comes from... y'know!?!? |
If the velocity
is 40m/s at 30°, the vertical and horizontal components will be 20m/s
and 34m/s, respectively.
From the initial vertical velocity component, the time to the highest point of the ball's trajectory is 2 s and the height reached is 20 m (using g = 10 m/s2). The time-of-flight is 2(2 s) = 4 s, and the range is 136 m. |