The quotient of two polynomials is called a rational expression. Rational
expressions are to polynomials what rational
numbers are to integers. The goal here is
to learn to do everything that you do with Rational
Numbers with rational expressions. The isn't too difficult as long as
you know two things well, rational number arithmetic
and polynomial factoring. If you need some
review on either of these please read Rational Numbers
or Factoring Polynomials. It is
also a good idea to have an understanding of finding LCMs
of numbers by prime factoring, because we
will be doing the same thing for polynomials. For review on that see How
to Prime Factor a Number and GCFs and LCMs.
Simplification
Simplification is also called reducing to lowest terms with number fractions.
When you reduce fractions to lowest terms you divide top and bottom by common
factors. See
Rational Numbers for an explanation
of why this can be done. With algebraic fractions you do the same thing, and
you must remember that it is only common
factors that you can divide
out. You normally keep track of what you are doing with this by factoring
the top and bottom and then crossing out any
factors that are the same
upstairs as downstairs, but make sure you remember that you are taking out
common factors, so you must factor before you cancel anything out, and you
can only cross out common
factors of the whole top and bottom, not
just anything that looks the same upstairs and downstairs. In general in algebra
if you are ever unsure about whether you can do something one way you can
test it out is to replace the variables with numbers and see if what you are
thinking about doing would still make sense.
Example 1:
Simplify.
Solution:
Explanation:
Before doing any simplifying we must factor in the style that we factor polynomials.
If these were numbers you'd actually do the addition and subtraction before
trying to take out a common factor, but you can't do that here, because you
don't know what x is. So the only way you can hope to take out a common factor
is to factor by the methods that you use to
factor
polynomials. In this case we are in luck, because both the top and the
bottom have common factors. And then when we factor them that way, we do in
fact get a common factor in the top and bottom that we can divide out. So
we divide top and bottom by 8 and we can show this in a kind of shorthand
notation by crossing out the two 8's. This kind of canceling notation is a
very useful shorthand, but you must be very careful not to misuse it. No,
we can't go any farther in this problem. Don't be tempted to cancel out the
x's, they are not factors. Neither x+2 nor x-2 will factor, so there can be
no more common factors to take out.
Example 2:
Simplify.
Solution:
Explanation:
Same thing here except that the factoring is a bit more complication. Here
the top is a
difference of squares and the bottom
is a
perfect square. I've written the canceling
in a funny sort of way that isn't really quite legal, but it works here. I
am canceling the p+5 upstairs with one of the p+5's downstairs, and as a quick
way of showing it I just crossing out the 2. Be careful if you do this. It
will only work if the exponent is 2. Otherwise you have to lower the exponent
by one. Again this is as far as we can go. The p's in the final expression
won't cancel, because they are not common factors. Neither p-5 nor p+5 will
factor.
Multiplication
To multiply rational expressions, multiply straight across, the numerator
by the numerator and the denominator by the denominator. See
Rational
Numbers for an explanation of why. You should also be sure to do cross
canceling to keep from having to simplify at the end. Factor everything in
sight and then cancel out any
factor that is upstairs with any
factor
that is downstairs, no matter where they are in the problem.
Example 3:
Multiply.
Solution:
Explanation:
Factor everything in sight and then start canceling.
For the first top we are looking for two numbers to multiply to 9 and add
to 10, so that is 1 and 9, but it is really -1 and -9 because the middle term
is negative. For the second bottom we are looking for two numbers to multiply
to 36 and subtract to 5. That would be 9 and 4. Since the middle term is negative
we want the bigger one, the 9 to be negative and the smaller one, the 4 to
be positive. See
Factoring Polynomials
for an explanation of this kind of thinking when factoring polynomials. Lots
of things cancel out here. I have color coded it so that you can see what
cancels with what. After canceling we multiply everything that is left. If
nothing is left there is always a 1.
Example 4:
Multiply.
Solution:
Explanation:
Here we need the
difference of cubes formula
to factor. It doesn't matter that the denominator of the second one won't
factor, because it is going to cancel out anyway. As to the form of the final
answer, in my class and probably in many other algebra classes it is considered
to be all right to leave your answer in factored form, because it is just
a lot of extra work doing something that you already have been tested on to
multiply everything out, and really factored form is just as good a form for
a polynomial as standard form.
Division
To divide, just like with numbers, you invert the second one and multiply.
See
Rational Numbers for an explanation why. To
multiply, see the instructions above.
Example 5:
Divide.
Solution:
Explanation:
Turn the second one upside down right away and after that everything goes
the same as with multiplication. Lots of factoring practice in one like this.
LCMs
For adding and subtracting rational expressions we need to be able to find
LCMs of polynomials. To do this we can use the same prime factoring method
that we use with numbers. See
GCFs and LCMs.
The idea is that the factorization of each of the polynomials has to occur
in the factorization of the LCM so that it will be a multiple, but we don't
want to use any more factors than necessary, so that it will be the LEAST
common multiple. Keep in mind if you get confused with this that your answer
must be a multiple of each of the given polynomials.
One thing that is different with polynomials is that when we are dealing
with numbers we don't normally use negative numbers, so it is not possible
for something to be only off by a minus sign from something else. This is
possible with polynomials, and it is good to know what to do about it. What
you do basically is that you ignore it. Signs of the whole polynomial don't
matter for LCMs, because you can always multiply one by -1 to get the other.
Example 6:
Find the LCM.
Solution:
Explanation:
We can use here the same prime factoring technique that we use with numbers,
except that here prime factoring is the kind of
factoring
that we do with polynomials. (See
GCFs and LCMs
for an explanation of the prime factoring technique for numbers.) We factor
the polynomials and put together the factors in the smallest way possible
so that each of the factorizations are contained in it. This means that we
include all of the factors to the highest powers that they occur in a single
polynomial. The first polynomial here is a perfect square. For the second
polynomial we are looking for two numbers that multiply to 28 and subtract
to 3. (See
Factoring Polynomials.) Then
we see that there are two prime factors, x+4, and x-7. The highest power of
x+4 is 2 and the highest power of x-7 is 1.
Example 7:
Find the LCM.
Solution:
Explanation:
Here the y-1 and the 1-y factors are only off by a factor of -1, which doesn't
matter for LCMs. We can tell that they are off by a factor of -1, because
they are reverse subtractions. Subtraction isn't commutative. The order makes
a difference with it, but it makes a difference in a very specific predictable
way. Try some numbers to see it for yourself. If you subtract 7-5 you get
2, but if you subtract 5-7 you get -2. Since factors of -1 don't matter for
LCMs whenever you want, you can reverse a subtraction. Remember, though, that
this doesn't mean that y-1 and 1-y are the same. They are just different in
a way that doesn't matter for finding LCMs. And it doesn't matter in the answer
either. If you gave the answer as 10(1-y), that would be okay too. It would
still by a multiple of the two polynomials, and no more complicated.
Addition and Subtraction
If the denominators are the same, just add or subtract the numerators. But
unlike with multiplication you may still have to simplify after this. If one
denominator is off by a factor of -1 from the other, you can fix that pretty
easily, you just multiply one of them top and bottom by -1. When the denominators
are totally different is when it get a bit trickier. Just like with numbers,
you have to find a common denominator. The common denominator is the LCM,
but you can't just change the denominators to the LCM for free, because that
would change the value of the expressions. You have to look and see what is
missing in the denominators and multiply top and bottom by that. See
Rational
Numbers for an explanation of why we have to do it this way.
Example 8:
Add.
Solution:
Explanation:
Here the denominators are the same, so we just add the numerators. But unlike
with multiplication there is no way to avoid having to simplify at the end,
but again you can't just cancel the x's, you have to first take the 2 out
as common factor. In the end we could have a 1 in the denominator, but 1's
in the denominator aren't necessary.
Example 9:
Add.
Solution:
Explanation:
Here the denominators are almost the same, but the differences are backward.
Even though I said that this doesn't make a difference for LCMs, there is
something that needs to be done in this case when we are adding, namely we
need to make the denominators the same by multiplying one of the fractions
top and bottom by -1. It doesn't really make a difference which one. It might
have even been better if I had used the other one. In this problem I multiplied
the second fraction top and bottom by -1 and that made it subtraction instead
of addition. Then the problem had another minus sign twist to it, which is
that when I factored in order to try to simplify it, it turned out that it
almost, but not quite had a common factor. Again we were off by a factor of
-1 which I factored out so that I could cancel. You don't really have to do
this quite so elaborately as this. If I were doing it on my own I which just
cancel the two differences that were reversed and replace the top one with
a minus sign or a -1. Also if you are in my class it is okay to leave it as
-1(2+r) or -(2+r), but it is better to at least use the second of these and
perhaps better to multiply it out, since that is a pretty simple multiplication.
Example 10:
Add.
Solution:
Explanation:
Now here we have one with totally different denominators, so we have to find
a proper
LCM. We factor the two polynomials (see
Factoring Polynomials for a review of how to
do this kind of factoring) and see that they have a common factor, which we
don't have to include twice in our
LCM. Since there
are no powers, we just include all of the factors that are there, without
any repetition, so we get the product of the three factors for our
LCM.
To see how to express each of these fractions as fraction with the
LCM
as the denominator what we have to do is look and see which factors are missing.
In the first fraction the y-1 is missing, so we multiply it top and bottom
by that. In the second fraction the y+2 is missing, so we multiply top and
bottom by that, and then we get something much uglier, but still it is something
we can deal with because we have common denominators. Once the denominators
are the same, just like before, we just add the numerators.
I tend to find it to be advisable in problems like this there are
complicated to write in some kind of substitute for the denominator, because
there is a lot to do with the numerator and copying the denominator over
and over again can get a bit tedious. I've written LCM here, but D for denominator
would do as well. This also has the advantage that it keeps you from trying
to cancel things out too soon in incorrect ways. Because of the very nature
of these problems with multiplying top and bottom by things in order to
get common denominators, it will always look like there is a common factor
to take out before you do the simplifying in the numerator, but this is
not the case, because you can only cancel common factors of the whole numerator.
There is no short way around it, you have to multiply each bit out and then
combine like terms, and then try to factor that before you can look for
anything to cancel.
After we get the numerator totally simplified, then we can put the denominator
back in. Then we can try to factor the numerator
and see if it has any common factors with the denominator. One thing that
is interesting here is that you can cheat a bit when you are factoring it,
because you don't really care if it factors, if it doesn't factor so that
one of the factors is the same as one of the ones in the denominator. So
here we can write (3y )(y
) as the form of the factorization and only consider possibilities where
there is a -1 or a 2 in the second factors, since there is no way for the
first factor to match up. It can't be a -1, since the terms are all positive,
so the only possibility would be the 2, which would have to be a factorization
of (3y+7)(y+2), but that gives a middle term of 13y, so it doesn't work.
Since this is the only possible factorization that could cancel with anything,
we don't really care if it factors any other way, so we leave it unfactored.
Example 11:
Perform the indicated operations.
Solution:
Explanation:
Here we have three fractions to deal with, so we need to find the
LCM
of all of them. This is not too bad since the third one is the product of
the other two, so it is the
LCM. What is missing
in the first fraction is y-1, so we multiply that top and bottom. What is
missing in the second fraction is y+3, so we multiply that top and bottom.
The third one already has the common denominator, so we don't have to change
it. Then we do the adding and subtracting in the numerator and do all of the
multiplying and combining like terms before putting the denominator back in.
The numerator simplified quite a lot, so it is easy to see that there is nothing
in it to cancel with the denominator and we are done.