
Calculus I using LiveMath
Chapter 3
The Quotient Rule
You just found in the last section that the derivative of the
product of two functions is not the product of their
derivatives. Likewise, the derivative of the quotient of two functions
is not the quotient of their derivatives.
LiveMath, again, makes it easy to demonstrate a rule of differentiation.
As with the past couple of examples, you will use the substitute
variables u and v to do this.
Example
3.9 The Quotient Rule
- Input the following two Props. The first defining a function
of a quotient; the second, the Derivative Op. Remember, the derivative
is taken with respect to x. You are assuming that both
u and v are functions of x. You put the
function in this form so you will get the intermediate answer
showing you the rule.
- Substitute the first Prop into the second (with Auto-Simplify
on).
To see this in action, define u and v
as simple functions of x.
- Try the following two.
- Substitute the first (u = x^3) and second (v=5x)
Props above into the Quotient Rule you achieved in the step above.
For the first step make sure Auto-Simplify is turned off. This
will show the substitution before it dissolves into the answer.
Use an Expand for the final answer.
- You can have LiveMath perform the differentiation in one
step by making the y-function contain the smaller functions from
the start.
Click on the LiveMath Internet icon below to see this last
example in action.
LiveMath Internet - Quotient Rule
Demo
The next example uses more complicated expressions to demonstrate
the Quotient Rule.
Example 3.10 The Quotient Rule
using real functions
- Differentiate the following function in a way that demonstrates
the Quotient Rule.
The subject of how to differentiate e^x is covered later in
the book. So, at this point, let LiveMath do the work and observe
the results. Careful observation may peak your curiosity in this
example.
- Set up the example as you did above making sure that, while
you perform the manipulations, you remember to switch Auto-Simplify
on and off at the appropriate times.
- The final answer is shown below. The intermediate manipulations
are left to you. You will find the Expand manipulation useful
in this example, along with a Collect, which produces the final
answer shown below.
What would you do if the numerator of the quotient was equal
to 1? In other words, how would you differentiate the following
function?

To find out, and to see how it extends the scope of the power
rule, click here.