| [i]+1 | Suppose this formula is associated to column Alice: .
Then, each row of column Alice will be assigned a value that is equal to the value of the corresponding row of column i (the index column) of the same worksheet plus one. |
| [i 5]+1 | Suppose this formula is associated to column Alice: .
Then, each row of column Alice will be associated a value that is equal to row number 5 of column i (the index column) of the same worksheet plus one. Since rows are counted from zero, row number 5 of the index column is actually the sixth row and has a value of 5. So the result is 6 for all values of Alice. |
| [Jupiter Alice] | Each row of the column this formula belongs to is associated a value corresponding to the value of the same row of column Alice of worksheet Jupiter. Note that column Alice of worksheet Jupiter must have enough rows. |
| [Jupiter Alice 21] | Each row of the column this formula belongs to is associated a value corresponding to row number 21 of column Alice of worksheet Jupiter. |
| sin(pi*[i])+[i]/2 | This is a more complex formula. See the result in this figure:
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